We must express a summation, with i index and lower limit 1, the following sum:
[tex]1+3+5+...+(2n-1).[/tex]We can write the terms as:
[tex](2*1-1)+(2*2-1)+...+(2*i-1)+...+(2*n-1).[/tex]We see that the general term is (2i - 1) and the upper limit is n. So the sum is:
[tex]\sum_{i\mathop{=}1}^n(2i-1).[/tex]Answer[tex]\sum_{i\mathop{=}1}^n(2i-1)[/tex]