Respuesta :

Answer:

Concept:

The area of the rectangle is given below as

[tex]\begin{gathered} A_{\text{rectangle}}=\text{length}\times width \\ A_{\text{rectangle}}=l\times w \\ \text{where,} \\ l=2\frac{3}{4}yd \\ w=\frac{2}{3}yd \end{gathered}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} A_{\text{rectangle}}=\text{length}\times width \\ =2\frac{3}{4}yd\times\frac{2}{3}yd \\ A_{\text{rectangle}}=\frac{11}{4}yd\times\frac{2}{3}yd \\ A_{\text{rectangle}}=\frac{11}{6}yd^2 \\ A_{\text{rectangle}}=1\frac{5}{6}yd^2 \end{gathered}[/tex]

Hence,

The final answer is

[tex]1\frac{5}{6}yd^2[/tex]

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