The rate of reading has been given as
[tex]\begin{gathered} 2\frac{7}{9}\text{ pages =1minute} \\ \text{If 1 minute is 2}\frac{7}{9},\text{ then it means any amount of time greater than 1 minute would simply be } \\ \text{Number of pages per minute times the number of minutes given} \\ \text{That is, 2 minutes would be 2}\frac{7}{9}\times2.\text{ And so on}\ldots \\ \text{Therefore, 4}\frac{5}{6}\min utes\text{ would be;} \\ 4\frac{5}{6}\min =2\frac{7}{9}\times4\frac{5}{6}pages \\ 4\frac{5}{6}\min =\frac{25}{9}\times\frac{29}{6}\text{pages} \\ 4\frac{5}{6}\min =\frac{725}{54}pages \\ 4\frac{5}{6}\min =13\frac{23}{54}pages \\ \end{gathered}[/tex]The results shows that she would read 13 23/54 pages in the time given
