In order to find the horizontal and vertical components of the given vector, we can use the formulas below:
[tex]\begin{gathered} V_x=V\cdot\cos\theta\\ \\ V_y=V\cdot\sin\theta \end{gathered}[/tex]So, if the magnitude of the resultant vector is 145 m/s and the angle is 55°, we have:
[tex]\begin{gathered} V_x=145\cdot\cos55°\\ \\ V_x=83.17\text{ m/s}\\ \\ \\ \\ V_y=145\cdot\sin55°\\ \\ V_y=118.78\text{ m/s} \end{gathered}[/tex]