Question

Four wires running through the corners of a square with sides of length 21.918 cm carry equal currents, 2.785 A. Calculate the magnetic field at the center of the square.

Answer 1

We will determine the magnetic field as follows:

$\begin{gathered} B=\frac{\mu_0I}{2r\pi} \\ \\ \Rightarrow B=\frac{(4\pi\ast10^{-7})(2.785)}{2\pi(0.21918\sqrt{2})}\Rightarrow B=1.796963578...\ast10^{-6} \\ \\ \Rightarrow B\approx1.8\ast10^{-6}T\Rightarrow B\approx1.8\mu T \end{gathered}$

So, the magnitude of the magnetic field is approximately 1.8 micro tesla.