Solve. Show your work.log6(2x – 4) + 11 = 13

ANSWER
x = 20
EXPLANATION
To solve this equation, first, we have to subtract 11 from both sides,
[tex]\begin{gathered} \log_6(2x-4)+11-11=13-11 \\ \\ \log_6(2x-4)=2 \end{gathered}[/tex]Then, there is the property of logarithms that states that if we raise the base of a logarithmic expression to the expression, the result is the argument of the logarithm,
[tex]a^{\log_a(b)}=b[/tex]So, the next step is to raise 6 to each side of the equation,
[tex]\begin{gathered} 6^{\log_6(2x-4)}=6^2 \\ 2x-4=36 \end{gathered}[/tex]Then, add 4 to both sides,
[tex]\begin{gathered} 2x-4+4=36+4 \\ 2x=40 \end{gathered}[/tex]And divide both sides by 2,
[tex]\begin{gathered} \frac{2x}{2}=\frac{40}{2} \\ \\ x=20 \end{gathered}[/tex]Hence, the solution is x = 20.