Question

f m∠DFC=(6b−18)°, find b so that FC−→−⊥FD−→−.I'm confused i know that its a 90 degree but i dont know where to plug the numbers

Answer 1

Given:

$\angle DFC=(6b-18)^{\circ}$

FC perpendicular to FD.

$\begin{gathered} \angle DFC=90^{\circ} \\ (6b-18)^{\circ}=90^{\circ} \\ 6b=90+18 \\ 6b=108 \\ b=18 \end{gathered}$