Respuesta :

Given:

Sample of 10 students is as below

[tex]12,15,8,9,14,8,17,14,8,15[/tex]

Required:

We want to find the mean absolute deviation for the given sample

Explanation:

For this,

first we need to find the mean of given sample

[tex]\frac{12+15+8+9+14+8+17+14+8+15}{10}=\frac{120}{10}=12[/tex]

Now

[tex]\begin{gathered} \text{l12-12l=0} \\ \text{l12-15l=3} \\ \text{l12-8l=4} \\ \text{l12-9l=3} \\ \text{l12-14l=2} \\ \text{l12-8l=4} \\ \text{l12-17l=5} \\ \text{l12-14l=2} \\ \text{l12-8l=4} \\ \text{l12-15l=3} \end{gathered}[/tex]

now find the mean of new sample for mean absolute deviation

[tex]\frac{0+3+4+3+2+4+5+2+4+3}{10}=\frac{30}{10}=3[/tex]

Final answer:

3

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