[tex]\begin{gathered} FE=28\cdot2 \\ FE=56 \\ 40=\frac{DG-FE}{2} \\ 40\cdot2=DG-FE \\ DG=40\cdot2+FE \\ DG=40\cdot2+56 \\ DG=136 \\ \text{The value of DG is 136} \\ DHG=\frac{DG+FE}{2} \\ DHG=\frac{136+58}{2} \\ \text{DHG}=\frac{194}{2} \\ \text{DHG}=97 \\ \text{The value of DHG is 97} \\ \text{You cant solve the all other arcs beacuse you need to know},\text{ the } \\ \text{value of the arc }DF\text{ or }GE \end{gathered}[/tex]
