Given the exponential expression:
[tex]e^a=b[/tex]We will rewrite the expression using a natural logarithm
so,
[tex]\begin{gathered} \ln e^a=\ln b \\ a\cdot\ln e=\ln b \\ a\cdot1=\ln b \\ a=\ln b \end{gathered}[/tex]so, the answer will be:
[tex]a=\ln b[/tex]