ANSWER
= sec(t)
EXPLANATION
First let's rewrite this in terms of sines and cosines:
[tex]\frac{\cot t}{\csc t-\sin t}[/tex]The cotangent is the reciprocal of the tangent:
[tex]\cot t=\frac{1}{\tan t}=\frac{\cos t}{\sin t}[/tex]And the cosecant is the reciprocal of the sine:
[tex]\csc t=\frac{1}{\sin t}[/tex]Replace into the given expression:
[tex]\frac{\cot t}{\csc t-\sin t}=\frac{\frac{\cos t}{\sin t}}{\frac{1}{\sin t}-\sin t}[/tex]We can add the two terms in the denominator:
[tex]\frac{\frac{\cos t}{\sin t}}{\frac{1}{\sin t}-\sin t}=\frac{\frac{\cos t}{\sin t}}{\frac{1-\sin ^2t}{\sin t}}[/tex]The denominators of each fraction get cancelled out:
[tex]\frac{\frac{\cos t}{\sin t}}{\frac{1-\sin^2t}{\sin t}}=\frac{\cos t}{1-\sin ^2t}[/tex]We still can simplify this a little further. Remember the identity:
[tex]\cos ^2t+\sin ^2t=1[/tex]If we solve it for cos²t:
[tex]\cos ^2t=1-\sin ^2t[/tex]We have the same expression of the denominator. So let's replace the denominator by cos²t:
[tex]\frac{\cos t}{1-\sin^2t}=\frac{\cos t}{\cos ^2t}[/tex]Simplify the square:
[tex]\frac{\cos t}{\cos^2t}=\frac{1}{\cos t}[/tex]And this is the secant of t:
[tex]\frac{1}{\cos t}=\sec t[/tex]