Respuesta :

ANSWER

= sec(t)

EXPLANATION

First let's rewrite this in terms of sines and cosines:

[tex]\frac{\cot t}{\csc t-\sin t}[/tex]

The cotangent is the reciprocal of the tangent:

[tex]\cot t=\frac{1}{\tan t}=\frac{\cos t}{\sin t}[/tex]

And the cosecant is the reciprocal of the sine:

[tex]\csc t=\frac{1}{\sin t}[/tex]

Replace into the given expression:

[tex]\frac{\cot t}{\csc t-\sin t}=\frac{\frac{\cos t}{\sin t}}{\frac{1}{\sin t}-\sin t}[/tex]

We can add the two terms in the denominator:

[tex]\frac{\frac{\cos t}{\sin t}}{\frac{1}{\sin t}-\sin t}=\frac{\frac{\cos t}{\sin t}}{\frac{1-\sin ^2t}{\sin t}}[/tex]

The denominators of each fraction get cancelled out:

[tex]\frac{\frac{\cos t}{\sin t}}{\frac{1-\sin^2t}{\sin t}}=\frac{\cos t}{1-\sin ^2t}[/tex]

We still can simplify this a little further. Remember the identity:

[tex]\cos ^2t+\sin ^2t=1[/tex]

If we solve it for cos²t:

[tex]\cos ^2t=1-\sin ^2t[/tex]

We have the same expression of the denominator. So let's replace the denominator by cos²t:

[tex]\frac{\cos t}{1-\sin^2t}=\frac{\cos t}{\cos ^2t}[/tex]

Simplify the square:

[tex]\frac{\cos t}{\cos^2t}=\frac{1}{\cos t}[/tex]

And this is the secant of t:

[tex]\frac{1}{\cos t}=\sec t[/tex]

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