One coulomb (C) of charge represents an excess or deficit of 6.24 x 10¹⁸ electrons, therefore:
[tex]\begin{gathered} \frac{9.4}{6.24\times10^{18}}=1.5\times10^{-18} \\ \\ Since_{\text{ }}it_{\text{ }}has_{\text{ }}lost_{\text{ }}electrons: \\ \\ +1.5\times10^{-18} \end{gathered}[/tex]
Answer:
+1.5x10⁻¹⁸ C
