Find a point-slope form for the line with slope
[tex] \frac{1}{5} [/tex] and passing through the point (-8,-4)
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The point-slope form for the line is
The slope is m
and point 1 (x1, y1)
(y - y1 ) = m (x - x1)
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The case m = 1/5 and the point (-8,-4); x1= -8; y1= -4
(y - (-4) ) = (1/5) (x - (-8))
(y + 4) = (1/5) (x +8)
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The point-slope form for the line is
(y + 4) = (1/5) (x +8)
