Answer:
[tex]v(t)=-1250t+12000[/tex]Explanations:
The linear equation that relates the value V in dollars to the time t in years can be expressed as;
[tex]v(t)=mt+b[/tex]where m is the slope
b is the "y-intercept"
If the value went from $12,000 at time t = 0, this can be written in a coordinate form as (0, 12000)
If the value depreciates linearly to $2000 after 8 years, this is expressed in coordinate form as (8, 2000)
Next is to get the slope of the line passing through the coordinate point (0, 12000) and (8, 2000)
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{2000-12000}{8-0} \\ m=-\frac{10000}{8} \\ m=-1,250 \end{gathered}[/tex]Next is to get the y-intercept of the line.
Substitute the coordinate (0. 12000) and m = -1,250
[tex]\begin{gathered} 12,000=-1250(0)+b \\ 12,000=b \\ \text{Swap} \\ b=12,000 \end{gathered}[/tex]Substitute m = -1,250 and b = 12,000 into the formula to have:
[tex]v(t)=-1250t+12000[/tex]This gives the linear equation that relates the value V in dollars to the time t in years.