Answer:
[tex]A=1,026\imaginaryI n^2[/tex]
Explanation: We have to find the total area of the figure shown, the total area would be the area of the triangle and the square:
[tex]\begin{gathered} A=A_T+A_S\rightarrow(1) \\ \\ A_T=\frac{1}{2}(B\times H) \\ \\ A_S=S^2 \end{gathered}[/tex]
plugging in the unknowns in the equation (1) gives the answer as follows:
[tex]\begin{gathered} H=35in \\ \\ \\ B=\sqrt{37in^2-35in^2} \\ \\ \\ A_T=2\times\frac{1}{2}(BH)=(35in\times\sqrt{37\imaginaryI n^2-35\imaginaryI n^2}) \\ \\ \\ A_T=(35in\times\sqrt{37\mathrm{i}n^2-35\mathrm{i}n^2})=35in\times\sqrt{144}=35in\times12in^2 \\ \\ \\ A_T=420in^2 \\ \\ \\ A_S=S^2 \\ \\ \\ S=2\times B=2\times12in=24in \\ \\ \\ A_S=24in^2=576in^2 \\ \\ \\ A=A_T+A_S\Rightarrow A=420in^2+576in^2 \\ \\ \\ A=1,026in^2 \end{gathered}[/tex]
