Respuesta :

To solve this exercise, we need to use the chain rule, shown below

[tex]\frac{dy}{dt}=\frac{d}{dx}y\cdot\frac{d}{dt}x[/tex]

Then, in our case

[tex]\frac{d}{dx}y=\frac{d(\sqrt[]{x+1})}{dx}=\frac{d((x+1)^{\frac{1}{2}})}{dx}=\frac{1}{2}(x+1)^{-\frac{1}{2}}[/tex]

Therefore,

[tex]\frac{d}{dt}y=\frac{1}{2\sqrt[]{x+1}}\cdot3[/tex]

Finally, evaluate dy/dt in y=5, as shown next.

[tex]\begin{gathered} y=5 \\ \text{and} \\ y=\sqrt[]{x+1} \\ \Rightarrow\sqrt[]{x+1}=5 \\ \Rightarrow\frac{d}{dt}y(5)=\frac{1}{2\cdot5}\cdot3=\frac{3}{10} \end{gathered}[/tex]

The answer is dy/dt=3/10, when y=5.

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