Question

A spring (k = 1000 N/m) has a length of 50 cm when zero to net force is applied to it. What will its length bewhen 230 N of force is applied to stretch it?

Answer 1

$\begin{gathered} K=1000N/m \\ F=230N \\ L=0.5+x \\ F=Kx \\ Solving\text{ x} \\ x=\frac{F}{K} \\ \\ x=\frac{230N}{1000N/m} \\ x=0.23m \\ Hence \\ L=0.5m+0.23m \\ L=0.73m \\ The\text{ length is 0.73N} \end{gathered}$