Question

A tennis racket strikes a tennis ball with a force of 39 N. The racket is in contact with the ball for 0.21 seconds. What is the magnitude of the change in momentum of the tennis ball?

Answer 1

Answer:

8.19 kg m/s

Explanation:

The change in momentum is equal to the impulse. This impulse is also calculated as the force times time, so

$\Delta p=F\cdot t$

Then, replacing F = 39 N and t = 0.21 s, we get:

$\Delta p=(39N)(0.21s)=8.19\text{ kg m/s}$

So, the change in momentum of the tennis ball is 8.19 kg m/s