Question

256 - 905425Rewrite a 5 in the formq) + b[E). What isOA 2:9 – 918 - 10:26 + 49.5 - 503- 2012 + 25OB. 206 – 9:5 + 4.12 - 5OC. 2-3 - 9:2 + 4. - 5OD 2:3 - 912 + 10

Answer 1

Given

$\frac{2x^6-9x^5+4x^2-5}{x^3-5}$

To rewrite the above expression as,

$q(x)+\frac{r(x)}{b(x)}$

and find q(x).

Explanation:

It is given that,

$\frac{2x^6-9x^5+4x^2-5}{x^3-5}$

That implies,

Therefore,

$\frac{2x^{6}-9x^{5}+4x^{2}-5}{x^{3}-5}=(2x^3-9x^2+10)+\frac{45-41x^2}{x^3-5}$

Hence,

$q(x)=2x^3-9x^2+10$