Question

$- 4y ^{3 } - 16y^{2} - 12 - 4$divide the polynomiala. simplify the answer as much as possible

Answer 1

The given polynomial :

$\frac{-4y^3-16y^2-12}{-4}$

Divide each term of the numerator by 4:

$\begin{gathered} \frac{-4y^3-16y^2-12}{-4}=\frac{-4y^3}{-4}-\frac{16y^2}{-4}-\frac{12}{-4} \\ \frac{-4y^3-16y^2-12}{-4}=y^3+4y^2+3 \end{gathered}$

Answer : y³ + 4y² + 3