graph the line passing through (1, -5) whose slope is m = 6/5

We know one point and the slope. Let's use this and the slope-point form to calculate an equation for the line:
[tex]\begin{gathered} y-(-5)=\frac{6}{5}(x-1)\rightarrow y+5=\frac{6}{5}x-\frac{6}{5} \\ \Rightarrow y=\frac{6}{5}x-\frac{31}{5} \end{gathered}[/tex]Put two points that belong to the line in the plane and connect them with a line. We'll use points:
[tex]\begin{gathered} (1,-5) \\ \text{and} \\ (6,1) \end{gathered}[/tex]The graph would be: