Question

How I do find the delta h for the reaction

Answer 1

Answer

ΔH = -276.6 kJ

Explanation

Given that:

N₂(g) + 3H₂(g) → 2NH₃(g); ΔH = -92.2 kJ

Then ΔH for the reaction 3N₂(g) + 9H₂(g) → 6NH₃(g) will be:

ΔH = 3 x -92.2 kJ = -276.6 kJ