Respuesta :

Given:

The point, (4, -3)

The line,

[tex]y=\frac{1}{2}x+5[/tex]

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

[tex]m=\frac{1}{2}[/tex]

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the point and slope we get,

[tex]\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}[/tex]

Hence, the equation in slope-intercept form for the line is,

[tex]y=\frac{1}{2}x-5[/tex]

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