Answer: We have to factor out the polynomial completely, the polynomial is as follows:
[tex]30y^2-16y+2\rightarrow(1)[/tex]The factorization steps for the polynomial (1) are as follows:
[tex]\begin{gathered} 30y^2-16y+2=2(15y^2-8y+1) \\ \\ \\ \\ (15y^2-8y+1)\rightarrow(15y^2-3y)+(-5y+1) \\ \\ \\ \\ 3y(5y-1)-(5y-1)\rightarrow(5y-1)(3y-1) \\ \\ \\ \\ \therefore\rightarrow \\ \\ \\ \\ 30y^2-16y+2=2(5y-1)(3y-1)\rightarrow(2) \end{gathered}[/tex]The final answer is the polynomial (2) in factored form.