Question

i need help please this is for my pre calculus class

Answer 1

To find the vertical asymptotes, we have to find the zeros of the denominator.

$x^2-x-2=0$

We have to find two numbers whose product is 2, and which difference is 1. Those numbers are 2 and 2.

$x^2-x-2=(x-2)(x+1)$

Then, the zeros are

$\begin{gathered} x=2 \\ x=-1 \end{gathered}$

Therefore, the vertical asymptotes are x = -1 and x = 2.