we have the expression
[tex]secxsin(\frac{\pi}{2}-x)[/tex]
Remember that
[tex]sin(A-B)=sinAcosB-cosAsinB[/tex]
therefore
[tex]\begin{gathered} sin(\frac{\pi}{2}-x)=sin\frac{\pi}{2}cosx-cos\frac{\pi}{2}sinx \\ \\ sin(\frac{\pi}{2}-x)=cosx \end{gathered}[/tex]
substitute in the given expression
[tex]\begin{gathered} secx(cosx) \\ (\frac{1}{cosx})cosx \\ 1 \end{gathered}[/tex]
The answer is 1
