Given:
[tex]\begin{gathered} Opposed\text{ \lparen American\rparen}=449 \\ Favoured\text{ \lparen American\rparen}=293 \\ Not\text{ }sure\text{ \lparen American\rparen}=258 \\ Total=1000 \end{gathered}[/tex]
To Determine: The probability of a randomly selected American was in favor
Solution
The probability of an event A is the ratio of the number of element in A to the total number of element in the sample space
[tex]\begin{gathered} P(A)=\frac{n(A)}{n(S)} \\ P(A)=Probability\text{ of event A} \\ n(A)=number\text{ of elements in A} \\ n(S)=number\text{ of elements in the sample space} \end{gathered}[/tex]
Apply the probability formula to solve for the probability of an event A is the ratio of the number of element in A to the total number of element in the sample space
Therefore,
[tex]\begin{gathered} P(F)=\frac{number\text{ of Americans in favor}}{total\text{ number of Americans}} \\ P(F)=Probability\text{ of American in favor} \\ P(F)=\frac{293}{1000} \\ P(F)=0.293 \end{gathered}[/tex]
Hence, the probability of a randomly selected American was in favor is 0.293