Question

Given the expression 3x^10-48x^2 Factor the expression completely. Show the steps and work please!

Answer 1

Answer:

$3x^2(x^4-4)(x^4+4)$

Explanation:

Here, we want to factorize the given polynomial completely

We proceed as follows:

$\begin{gathered} 3x^{10}-48x^2 \\ 3x^2(x^8-16) \end{gathered}$

Now, for the value inside the bracket, we can use the difference of two squares

We have that in the general form as:

$a^2-b^2\text{ = \lparen a +b\rparen\lparen a-b\rparen}$

Thus, applying that to the factorization:

$3x^2(x^4-4)(x^4+4)$