Solution:
Given the equation:
[tex]x-y-=-4[/tex]To sketch the graph of the above equation,
step 1: Evaluate the value of y, when x equals zero
Thus,
[tex]\begin{gathered} x-y=-4 \\ when\text{ x=0, we have} \\ 0-y=-4 \\ \Rightarrow y=4 \end{gathered}[/tex]step 2: Evaluate the value of x, when y equals zero.
Thus,
[tex]\begin{gathered} x-y=-4 \\ when\text{ y=0, we have} \\ x-0=-4 \\ \Rightarrow x=-4 \end{gathered}[/tex]step 3: Plot the obtained points in steps 1 and 2 on a graph.
Thus, the points are
[tex]\left(0,4\right?\text{ and \lparen-4,0\rparen}[/tex]The graph of the equation is as shown below:
MIdpoint: The midpoint (x,y) between two points is expressed as
[tex]\begin{gathered} \lparen x,y)=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right? \\ where \\ \lparen x_1,y_1)\text{ and \lparen x}_1,y_1)\text{ are the coordinates of the endpoints} \end{gathered}[/tex]Given the points (-1,4) and (-4,1), we have
[tex]\begin{gathered} x_1=-1 \\ y_1=4 \\ x_2=-4 \\ y_2=1 \end{gathered}[/tex]Thus, the midpoint of the points (-1,4) and (-4, 1) is evaluated as
[tex]\begin{gathered} \lparen x,y)=\left(\frac{-1+\left(-4\right)}{2},\frac{4+1}{2}\right? \\ =\left(\frac{-1-4}{2},\frac{4+1}{2}\right? \\ =\left(-\frac{5}{2},\frac{5}{2}\right? \\ \Rightarrow\left(x,y\right)=\left(-2.5,\text{ 2.5}\right? \end{gathered}[/tex]Hence, the midpoint between (−1,4) and (−4,1) is (-2.5, 2.5).