Question

A party man is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg How much of each should be added to obtain 60 kg of a mix.that will sell for $1.90 per kg?

Answer 1

Given:

Nuts = $2.50

Cereal mixture = $1

Find -: How much each should be added.

Sol:

Obtain = 60 kg.

Let nuts = x kg

Cereal = y kg

To obtain 60 kg means:

$\begin{gathered} x+y=60 \\ \\ y=60-x \end{gathered}$

Pricing at $1.90 per kg means:

$\begin{gathered} x(2.50)+y(1)=60(1.90) \\ \\ 2.5x+y=114 \end{gathered}$

Put the value of "y" then:

$\begin{gathered} 2.5x+60-x=114 \\ \\ 1.5x=114-60 \\ \\ 1.5x=54 \\ \\ x=\frac{54}{1.5} \\ \\ x=36 \end{gathered}$

Then the value of "y" is:

$\begin{gathered} y=60-x \\ \\ y=60-36 \\ \\ y=24 \end{gathered}$

So,

In the mixture 36 kg of nuts and 24 kg of cereal.