The first thing we have to see is that exercise (c) is given as follows
[tex](c)_{}\to\frac{-4}{f(k)}[/tex]From (e) we know:
[tex]f(k)=-4k+7[/tex]So we replace f(k) of the (e) part on the (c) part as follows:
[tex]f(k)=\frac{-4}{(-4k+7)}[/tex]Now we must find the value of x the function F (k) is not defined. This value is given when the denominator of the function gives 0 since the function would be indeterminate then:
[tex]\begin{gathered} -4k+7=0 \\ -4k=-7 \\ k=\frac{7}{4} \end{gathered}[/tex]All functions have a domain and a range. The domain of a function is all the values that the function can take along the k-axis and the range on the f(k)-axis.