Given MK is perpendicular to MJ and MJ is perpendicular to MK and MN is congruent to KJ prove MJN equals JMK

m∠KNJ is perpendicular as well as m∠MJN, so m∠KNJ ≅ m∠MJN
MN is congruent to KJ, MN ≅ KJ
And MJ is congruent to JM by the reflexive property
Then ΔMJN is congruent to ΔJMK by SAS congruence
1) Considering that we can sketch it:
0. m∠KNJ is perpendicular as well as m∠MJN, so m∠KNJ ≅ m∠MJN
,1. MN is congruent to KJ, MN ≅ KJ
,2. And MJ is congruent to JM by the reflexive property
,3. Then ΔMJN is congruent to ΔJMK by ,SAS congruence
2) Hence, there are two congruent triangles by Side Ange Side
congruence.
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