Question

Assume perfectly inelastic collision, solve for finalvelocity of m1.m1= 10.00 kg V10=2.00 m/s m2= 10.00 kg V20=0 m/sVIfim/s Round your answer to 3 significant figures

Answer 1

Take into account that after the impact, the two objects move stick together.

Then, by using the law of conservation of total momentum, you can write the following equation:

$m_1v_{1o}+m_2v_{2o}=(m_1+m_2)v$

Solve the previous equation for v, replace the values of the other parameters and simplify:

$\begin{gathered} v=\frac{m_1v_{1o}+m_2v_{2o}}{m_1+m_2}=\frac{(10.00kg)(2.00\frac{m}{s})+(10.00kg)(0.00\frac{m}{s})}{10.00\operatorname{kg}+10.00\operatorname{kg}} \\ v=1.00\frac{m}{s} \end{gathered}$

Now, consider that the speed v is the final speed of both objects, that is,

v = v1f = v2f

Hence, you can conclude that v1f = 1.00m/s