Question

Hello, please help me with this geometry on circles and ratios.

Answer 1

To determine the tangent angle of a circle

$\begin{gathered} arcBDC\colon arcBC=3\colon2of360^0\text{ } \\ arc\text{ BDC = }\frac{3}{5}X360^0=216^0 \\ arc\text{ BC = }\frac{2}{5}x360^0=144^0 \end{gathered}$

Measure of angle A = 1/2 of arc BDC - arc BC

[tex]\begin{gathered} mHence the measure of angle 36°