We have to solve the equation
[tex]-\frac{1}{4}(x+2)+5=-x[/tex]So we are going to let the variable x in one side of the equation and the constants (the numbers) in the other, but fisrt we open the parentheses
[tex]\begin{gathered} -\frac{1}{4}x-\frac{2}{4}+5=-x \\ \\ -\frac{1}{4}x-\frac{1}{2}+5=-x \end{gathered}[/tex]Now we can solve for x
[tex]\begin{gathered} -\frac{1}{4}x+x-\frac{1}{2}+5=-x+x \\ \\ \frac{3}{4}x+\frac{9}{2}=0 \\ \\ \frac{3}{4}x+\frac{9}{2}-\frac{9}{2}=-\frac{9}{2} \\ \\ \frac{3}{4}x=-\frac{9}{2} \\ \\ x=\frac{4}{3}\cdot(-\frac{9}{2}) \end{gathered}[/tex]So we have that
[tex]x=-\frac{36}{6}=-6[/tex]So the answer is x = - 6.