Question

I would like somebody to verify my solution for this particular problem!

Answer 1

Step 1

Given;

$\begin{gathered} x(t)=t-2 \\ y(t)=2t^2+4 \\ t\text{ is on the interval \lbrack-3,1\rbrack} \end{gathered}$

Required; To write in standard form.

Step 2

$\begin{gathered} x=t-2 \\ t=x+2 \end{gathered}$$\begin{gathered} y(t)=2(x+2)^2+4 \\ y(t)=2x^2+8x+12 \\ \end{gathered}$

The answer will be;

$y=2x^2+8x+12\text{ where x is on the interval \lbrack}$