Question

Given lines 1, m and n are all parallel and cut by two transversal lines, find the value of x. 11 m 33 6 n

Answer 1

In the given figure, lines l, m, and n are parallel.

These parallel lines are cut by two transversal lines proportionally.

So, we can set up the following proportion.

$\frac{x}{6}=\frac{11}{33}$

Let us solve for x.

$\begin{gathered} \frac{x}{6}=\frac{11}{33} \\ x=6\cdot\frac{11}{33} \\ x=2 \end{gathered}$

Therefore, the value of x is 2