Respuesta :

The probability of 2 consecutive events is the product of the probabilities of the single events.

The probability (P) of a single event A is:

[tex]P(A)=\frac{number\text{ }of\text{ }favorable\text{ }outcomes}{t=number\text{ }of\text{ total }outcomes}[/tex]

So, let's find the probability of the first event:

Event: Landing on a number less than 6.

Number of Favorable outcomes: 2 (Landing on 6 or 7).

Total outcomes: 3 (Landing on 6, 7, or 8).

Then,

[tex]P(A)=\frac{2}{3}[/tex]

Now, let's find the probability of the second outcome:

Number of Favorable outcomes: 1 (Landing on 6 ).

Total outcomes: 3 (Landing on 6, 7, or 8).

[tex]P(B)=\frac{1}{3}[/tex]

Then, the probability of landing on a number less than eight and then landing on a 6 ​is:

[tex]\begin{gathered} P=P(A)*P(B) \\ P=\frac{2}{3}*\frac{1}{3} \\ P=\frac{2}{9} \end{gathered}[/tex]

Answer: 2/9.

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