Given that
The equation is y = -2x + 4 and we have to find the line perpendicular to the given line and pass through the point (4, 2).
Explanation -
Since the two lines are parallel when the product of their slopes is -1.
[tex]\begin{gathered} Let\text{ the slope of given line is m}_1\text{ and slope of line to be found is m}_2. \\ Then,\text{ } \\ m_1\times m_2=-1 \end{gathered}[/tex]On comparing the given line with the general equation,
y = mx + c
we have m = slope = -2
[tex]\begin{gathered} So\text{ we have} \\ m_1=-2 \\ Then \\ -2\times m_2=-1 \\ m_2=\frac{1}{2} \end{gathered}[/tex]Now we have to find the line with a slope 1/2 and pass through the point (4, 2).
[tex]\begin{gathered} y-2=m_2(x-4) \\ y-2=\frac{1}{2}(x-4) \\ y-2=\frac{x}{2}-\frac{4}{2} \\ y-2=\frac{x}{2}-2 \\ y=\frac{x}{2}=\frac{1}{2}x \end{gathered}[/tex]So the required line is y = x/2 and the correct option is D.
Final answer -
Hence the final answer is y = x/2