Use the given conditions to write an equation for the line in point-slope form and slope-intercept form Passing through (-2,4) and parallel to the line whose equation is x-3y = 7

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Answer:

The equation for the line is:

3y - x = 14

Explanation:

Given the line:

x - 3y = 7

This line can be written as:

y = (1/3)x - 7/3

The slope is 1/3

The y-intercept is -7/3

A line parallel to this has the same slope but different y-intercept, written as:

y = (1/3)x + b

Using the given point (-2, 4), with x = -2 and y = 4, we can obtain the value of b

4 = (1/3)(-2) + b

b = 4 + 2/3

= 14/3

Therefore, the line is:

y = (1/3)x + (14/3)

or

3y - x = 14

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