Given that three less than the quotient of ten and a number, increased by six
Let n be a number.
A quotient of ten and a number can be represented as follows.
[tex]\frac{10}{n}[/tex]
three less than the quotient of ten and a number
Subtract 3 from the quotient of ten and a number.
[tex]\frac{10}{n}-3[/tex]
three less than the quotient of ten and a number, increase by six.
Add 6 to the three less than the quotient of ten and a number.
[tex]\frac{10}{n}-3+6[/tex]
Substitute n=2, we get
[tex]\frac{10}{2}-3+6=5-3+6=11-3=8[/tex]
The answer is 8.
