This is not a question from a graded test or assessment. Instructions: Give me 5 points when graphing the equation. All numbers must be less than or equal to 10. All numbers must be more than or equal to -10.

We must plot the function:
[tex]f(x)=\log_{\frac{1}{2}}(x).[/tex]With values -10 ≤ x ≤ 10 and -10 ≤ y ≤ 10.
Taking into account the properties of logarithms:
[tex]\begin{gathered} \log_a(x^b)=b\cdot\log_a(x), \\ \log_a(a)=1. \end{gathered}[/tex]We evaluate the function at x = 1/2, 1, 2, 4 and 8:
[tex]\begin{gathered} f(\frac{1}{2})=\log_{\frac{1}{2}}(\frac{1}{2})=1, \\ f(1)=\log_{\frac{1}{2}}(1)=0, \\ f(2)=\operatorname{\log}_{\frac{1}{2}}(2)=\operatorname{\log}_{\frac{1}{2}}((\frac{1}{2})^{-1})=-1\cdot\operatorname{\log}_{\frac{1}{2}}(\frac{1}{2})=-1, \\ f(4)=\operatorname{\log}_{\frac{1}{2}}(4)=\operatorname{\log}_{\frac{1}{2}}((\frac{1}{2})^{-2})=-2\cdot\operatorname{\log}_{\frac{1}{2}}(\frac{1}{2})=-2, \\ f(8)=\operatorname{\log}_{\frac{1}{2}}(8)=\operatorname{\log}_{\frac{1}{2}}((\frac{1}{2})^{-3})=-3\cdot\operatorname{\log}_{\frac{1}{2}}(\frac{1}{2})=-3. \end{gathered}[/tex]Plotting these values and the function, we get the following graph:
AnswerPoints:
• (1/2, 1)
,• (1, 0)
,• (2, -1)
,• (4, -2)
,• (8, -3)
Graph: