Given
The points (2,1) and (-2,-2).
To graph the line that passes through the given points and to find the equation of the line.
Now,
It is given that, the points (2,1) and (-2,-2).
The graph of the line which passes through (2,1) and (-2,-2) is,
Therefore, the equation of the line is,
[tex]\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}[/tex]Then, for (2,1) and (-2,-2), the equation of the line is,
[tex]\begin{gathered} \frac{y-1}{-2-1_{}}=\frac{x-2}{_{}-2-2_{}} \\ \frac{y-1}{-3}=\frac{x-2}{-4} \\ 4(y-1)=3(x-2) \\ 4y-4=3x-6 \\ 3x-4y-6+4=0 \\ 3x-4y-2=0 \end{gathered}[/tex]Hence, the equation of the given line is 3x-4y-2=0.