Question

Find the derivative :y = (x+3)/(2x+1)

Answer 1

given that

$y=\frac{x+3}{2x+1}$

Differentiating we get

$\begin{gathered} \frac{dy}{dx}=\frac{(2x+1)-2(x+3)_{}}{(2x+1)^2} \\ =\frac{2x+1-2x-6}{(2x+1)^2} \\ =\frac{-5}{(2x+1)^2} \end{gathered}$