[tex]h(x)=x^2-5x-6[/tex]
1. Find the axis of symmetry: Use the next formula:
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ \text{axis of si}mmetry\colon \\ x=-\frac{b}{2a} \end{gathered}[/tex][tex]\begin{gathered} x=-\frac{-5}{2(1)} \\ \\ x=\frac{5}{2} \\ \\ x=2.5 \end{gathered}[/tex]
Axis of symmetry: x=2.5
2. Find the vertex: x-coordinate of the vertex is the value of the axis of simmetry, use it to find the y-coordinate of the vertex:
[tex]\begin{gathered} h(\text{2}.5)=(2.5)^2-5(2.5)-6 \\ h(\text{2}.5)=6.25-12.5-6 \\ h(2.5)=-12.25 \end{gathered}[/tex]
Vertex: (2.5, -12.25)
3. x-intercepts: Equal the function to 0 and solve x:
[tex]\begin{gathered} x^2-5x-6=0 \\ \\ \text{Factor:} \\ x^2+x-6x-6=0 \\ x(x+1)-6(x+1)=0 \\ (x+1)(x-6)=0 \\ \\ \text{Solve x:} \\ x+1=0 \\ x=-1 \\ \\ x-6=0 \\ x=6 \end{gathered}[/tex]
x-intercpets: (-1,0) and (6,0)
4. Find y-intercept: Evaluate the function when x=0:
[tex]\begin{gathered} h(0)=0^2-5(0)-6 \\ h(0)=0-0-6 \\ h(0)=-6 \end{gathered}[/tex]
x-intercept: (0,-6)
5. Graph: