Question

What is the value of (x^2 + (2y)) ÷ ((2w) + 3z) for w = 2, x = 5, y = 8, and z = 3?

Answer 1

Answer:

For w = 2, x = 5, y = 8, and z = 3,

$\frac{x^2+2y}{2w+3z}=\frac{41}{13}$

Explanation:

Given the expression:

$\frac{x^2+2y}{2w+3z}$

for w = 2, x = 5, y = 8, and z = 3, we have:

$\begin{gathered} \frac{5^2+2(8)}{2(2)+3(3)} \\ \\ =\frac{25+16}{4+9} \\ \\ =\frac{41}{13} \end{gathered}$