Question

a metal alloy weighing 6 mg and containing 32% gold is melted and mixed with 12 mg of a different alloy which contains 2% gold. what % of the resulting alloy is gold? explain all of your work.

Answer 1

12% of the resulting alloy is gold

Here, we want to calculate the percentage of the resulting alloy that is gold

We proceed as follows;

(32% of 6mg) + (2% of 12mg)

That would be;

1.92 + 0.24 = 2.16

What means that of the total (6mg + 12mg) , 2.16 mg is gold

Thus the gold percentage will be;

$\frac{2.16}{18}\text{ }\times\text{ 100 = 12 percent}$