From the terms of the sequence we are given, we can deduce that the next term of the sequence will be the previous one plus 3. Knowing this, the series we must consider is:
[tex]\sum ^{19}_{n\mathop=0}4+3(n)[/tex]And adding all the terms together we get
[tex]\sum ^{19}_{n\mathop=0}4+3(n)=650[/tex]