darin wrote 1 1/2 as the sum of three fractions. none of the fractions had a denominator of 2 what fractions might darin have used A 1/8+2/8+2/4 B2/8+3/8+5/8 C2/4+2/4+2/4 D3/4+2/4+2/4

Respuesta :

[tex]1\text{ }\frac{1}{2}\text{ }[/tex]

Step 1: To find the expression wherein the above can be a sum of three fractions, lets first convert to improper fraction

[tex]\begin{gathered} 1\frac{1}{2}\text{ =}1+\frac{1}{2} \\ =\frac{1}{1}+\frac{1}{2}=\frac{2+1}{2} \\ =\frac{3}{2} \end{gathered}[/tex]

Step 2: Check the options given

Then, let's check option A

[tex]\frac{1}{8}\text{ + }\frac{2}{8}\text{ +}\frac{2}{4}\text{ = }\frac{1}{8}\text{ + }\frac{2}{8}\text{ +}\frac{4}{8}\text{ =}\frac{7}{8}[/tex]

Option A is wrong

Let's try option B

[tex]\frac{2}{8}\text{ +}\frac{3}{8}\text{ + }\frac{5}{8}\text{ = }\frac{10}{8}\text{ =}\frac{5}{4}[/tex]

Option B is wrong

Let's try option C

[tex]\frac{2}{4}\text{ +}\frac{2}{4}+\frac{2}{4}\text{ =}\frac{6}{4}\text{ =}\frac{3}{2}[/tex]

Option C is correct

lets also check for option D

[tex]\frac{3}{4}\text{ +}\frac{2}{4}+\frac{2}{4}=\frac{7}{4}[/tex]

Option D is wrong

The answer is option C

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