From the problem, we have :
[tex]\lvert5-x\rvert>6[/tex]In solving absolute values, we need to take the positive and negative values of the terms outside the absolute value sign.
This will be :
[tex]\begin{gathered} 5-x>6 \\ 5-x>-6 \end{gathered}[/tex]We will form two inequalities.
Solve for the solutions :
For the first inequality,
[tex]\begin{gathered} 5-x>6 \\ -x>6-5 \\ -x>1 \\ \text{Note that multiplying a negative number will change the symbol} \\ \text{Multiply by -1} \\ x<-1 \end{gathered}[/tex]For the second inequality,
[tex]\begin{gathered} 5-x>-6 \\ -x>-6-5 \\ -x>-11 \\ \text{Multiply by -1} \\ x<11 \end{gathered}[/tex]So we have x < -1 and x < 11
From these two solutions, x < -1 will govern since that inequality needs a value of x less than -1 and some of the numbers less than 11 will not apply to it.
So the answer is x < -1
The graph will be :
The end point is an open circle because the symbol is <