Respuesta :

From the problem, we have :

[tex]\lvert5-x\rvert>6[/tex]

In solving absolute values, we need to take the positive and negative values of the terms outside the absolute value sign.

This will be :

[tex]\begin{gathered} 5-x>6 \\ 5-x>-6 \end{gathered}[/tex]

We will form two inequalities.

Solve for the solutions :

For the first inequality,

[tex]\begin{gathered} 5-x>6 \\ -x>6-5 \\ -x>1 \\ \text{Note that multiplying a negative number will change the symbol} \\ \text{Multiply by -1} \\ x<-1 \end{gathered}[/tex]

For the second inequality,

[tex]\begin{gathered} 5-x>-6 \\ -x>-6-5 \\ -x>-11 \\ \text{Multiply by -1} \\ x<11 \end{gathered}[/tex]

So we have x < -1 and x < 11

From these two solutions, x < -1 will govern since that inequality needs a value of x less than -1 and some of the numbers less than 11 will not apply to it.

So the answer is x < -1

The graph will be :

The end point is an open circle because the symbol is <

Ver imagen JaymonK156102
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